Robert (Bob) Bosch
@baabbbaash
I have two wolves inside me—a mathematician and an artist—and I feed them equally well. All of my art is made without AI. I find generative AI repulsive. I have no desire to use it, nor do I wish to collaborate with anyone who uses it.
The same decomposition but with one additional swap (yellow and black).
The large image on the right shows a 24x24 section of a decomposition of the infinite knight's graph into four 2-factors The four smaller images on the left show the four 2-factors. Here, the yellow and blue 2-factors are translations of each other, and the same is true for the black and red.
The same decomposition after one additional color swap (yellow and black).
The large image on the right shows a 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The four smaller images on the left show the four individual 2-factors.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
A 24x24 section of a decomposition of the infinite knight's graph into four 2-factors. The vertices are where eight "strands" meet at a point. If you zoom in, you'll see that each vertex has two yellow strands, two blue strands, two black strands, and two red strands.
Cover art for the May 2026 issue of the Notices of the American Mathematical Society. Here's a link to the issue: www.ams.org/notices
I converted a text message into a knight's tour. To decode it, follow the knight's tour, starting in the top left corner. The knight will traverse a succession of 11x11 tours, and each of these 11x11 tours corresponds to a letter. The message is a quote from Ursula K. Le Guin.
"Spiraling to keep myself from spiraling." An open knight's tour of a 99x99 chess board. The tour can be thought of as a tour of 11x11 tours, and it can be extended indefinitely to form an infinite Hamiltonian path through the infinite knight graph.
A tour of tours, an open knight's tour of an 99x99 chessboard. The tour starts in the bottom left corner and ends near the top right corner.
A single-line drawing that is simultaneously an open knight's tour of a 99x99 chessboard and a 3x3 Latin square.
Two knight's tour (32x32 and 64x64). Two terms of an infinite sequence of tours.
An open knight's tour of a 128x128 chessboard. The knight starts in the lower left corner, finishes near the lower right corner, and visits each of the sixteen 32x32 regions in the same order that they'd be visited by a second-stage Hilbert curve. #mathart